Subtitles section Play video Print subtitles The following content is provided under a Creative Commons license. Your support will help MIT OpenCourseWare continue to offer high quality educational resources for free. To make a donation or to view additional materials from hundreds of MIT courses, visit MIT OpenCourseWare at ocw.mit.edu. MICHAEL SHORT: So today is going to be the last day of neutron physics. As promised, we're going to talk about what happens as a function of time when you perturb the reactor, like you all did about a month ago. Did any of you guys notice the old-fashioned analog panel meter that said, reactor period, when you were doing your power manipulations? We're going to do that today. And you're going to explore that on the homework. So I'm arranging for all of your actual power manipulation traces to be sent to you. So each one, you'll have your own reactor data. You'll be able to describe the reactor period and see how well it fits our infinite medium single group equations, which it turns out is not very well. But that's OK, because you'll get to explain the differences. First, before we get into transients I wanted to talk a bit about criticality and perturbing it. So let's say we had our old single group kit criticality relation. And I'd like to analyze, just intuitively or mentally with you guys, a few different situations. Let's say we're talking about a light water reactor or a thermal reactor, like the MIT reactor, or pretty much all the reactors we have in this country. What sort of things could you do to perturb it? And how would that affect criticality? For example, let's say you shoved in a control rod. Let's take the simplest scenario. Control rods in. What would happen to each of the terms in the criticality condition? And then, what would happen to k effective? So let's just go one by one. Does nu ever change, ever? Actually, yeah, it does. Over time, you'll start-- that nu right there, remember, that's a nu bar, number of neutrons produced per fission. As you start to consume U238 add neutrons. And as you guys saw through a complicated chain of events on the exam, eventually make plutonium 239, which is a fissile fuel. The nu for 238 is actually different than the nu for 239. So I don't want to say that nu never changes. It's just that shoving the control rods into the reactor is not going to change nu. But it does change slowly over time as you build up plutonium. What about sigma fission? If this were a blended homogeneous reactor or a reactor in a blender, what would happen to sigma fission as you then shove in an absorbing material? Does it change? AUDIENCE: No. MICHAEL SHORT: You say, no. And I'm going to add here homogeneous. So in this case, remember if we define the average sigma fission as a sum-- I'll add bits to it-- of each material's volume fraction, or let's say atomic fraction, times each material's sigma fission, if we throw nu materials into the reactor, then this homogeneous sigma fission does change when we put materials in or take materials out. So you guys want to revise your idea? AUDIENCE: Yes. MICHAEL SHORT: Yes, thank you. There's only one other choice. Now the question is, by how much? If you put in a control rod where let's say the control rod's sigma fission would be equal to zero, but volume would be equal to small. Can't be any more specific than that. How much of an effect do you think you'll have on sigma fission? AUDIENCE: Small. MICHAEL SHORT: Very small. So let's say a little down arrow like that. What about sigma absorption? The volume is still small, but a control rod by definition sigma absorption equals huge. So what do you think? AUDIENCE: It's going to increase. MICHAEL SHORT: It's going to increase a little or a lot? AUDIENCE: A lot. MICHAEL SHORT: Quite a bit. Now let's look at the diffusion constant. And remember that the diffusion constant is 1 over 3 sigma total, minus the average cosine scattering angle sigma scattering. What do you think is going to happen to the neutron diffusion coefficient as you throw in an absorbing material? Something that's got an enormous absorption cross-section is also going to have an enormous total cross-section, because sigma total is sigma absorption plus sigma scattering. And sigma scattering doesn't change that much. But if sigma absorption goes up, sigma total goes up. If sigma total goes up, then what happens o the diffusion coefficient? AUDIENCE: Decrease. MICHAEL SHORT: Yep, it's got a decrease. And how does inserting a control rod change the geometry? AUDIENCE: It doesn't. MICHAEL SHORT: Very, very close. Yeah, you're right. The control rod better not change the geometry, but what I do want to remind you of is that this buckling term includes-- let's say, this was a one dimensional infinite slab Cartesian reactor. That little hot over there means we have some extrapolation distance. Remember, if we were to draw our infinite reactor with the thickness A and we wanted to draw a flux profile on top of that, it would have to be symmetric about the middle. And let's say we had our axis of this is x and this is flux. Flux can't go to zero right at the edge of the reactor, because that would mean that no neutrons were literally leaking out. So there's going to be some small extrapolation distance equal to about two times the diffusion coefficient. So the geometric buckling is actually pi over the reactor geometry, plus 2 times the diffusion coefficient. And if the diffusion coefficient goes down, but it's also very, very small compared to the geometric buckling, how much does the buckling change and by how much? And in what direction? AUDIENCE: It increases very slightly. MICHAEL SHORT: Increases very slightly. So the buckling might increase very slightly. What's the overall net effect on k effective? AUDIENCE: It goes down. MICHAEL SHORT: Should go down, you would hope. If you put a control rod in, it should make k effective go down, because there's a little decrease here. Things kind of cancel out there. But the big one is putting an absorption material, like a control rod in, should make k effective go down. And that's the most intuitive one, but you can work out one term at a time what's generally going to happen. So let's now look at some other scenarios for the same criticality condition. I'll just rewrite it so that we can mess it all up again. Now we want to go for the case of boil or void your coolant. And now we're getting into the concept of different feedback mechanisms. We've already talked once about how raising the temperature of something tends to increase cross-sections in certain ways. But now let's say, what would happen if you boil your coolant? If things got really hot and the water started to boil. What do you want to happen to k effective? You want it to increase? AUDIENCE: Decrease. MICHAEL SHORT: Decrease, thank you. You want it to decrease, or else you'd get a Chernobyl. And we'll talk about how that happened in a week or two.