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  • Hi, my name is Madeleine and I've just finished my second year of Engineering at Jesus College,

  • Cambridge. I applied in 2012 and matriculated in 2013. I'm going to go through 2 interview

  • questions which are taken from the website I want to study Engineering.org which is a

  • website which has hundreds of engineering interview type questions with worked through

  • answers and occasionally videos too. The two questions that I'm going to do are similar

  • to the kind of questions that I got during my interviews. So hopefully this will help.

  • So the first question reads as follows. On a clear day, you are on an airplane which

  • is 38,000 ft above the middle of Pacific Ocean. Taking the radius of the Earth to be 6,400km,

  • what is the approximate distance between you & the horizon of the Earth? You are also given

  • that 1 foot is equivalent to 0.3048 meters.

  • So the first thing that I would do is convert the 30000 feet into meters using the given

  • conversion. So 38 000 ft times by 0.3084 meters is roughly, using a calculator, 11.6km So

  • now that you have all of the figures in meters or km, you can then draw a diagram of the

  • earth with the center here and you can say that the airplane is hereish. So now marking

  • the distances on, you know that this, the radius of the earth, is 6400km. I'm just

  • going to say all the distances are in Km. Then the distance from the plane to the Pacific

  • Ocean is, as we calculated here, 11.6kms. So now we need to think about where the horizon

  • is. So the horizon is the line of sight from where you are in the airplane to the first

  • point you can see. By definition or by intuition, you can say that point has to be at right

  • angles with the radius of the earth because if you are looking at this way and say that

  • this is your line of sight and this is with the horizon and it's essentially where your

  • line is horizontal with the circumference of the earth. So if we then draw the radius

  • of the earth on to this point you know this has to be a right angle and, so from then

  • on, it's essentially a Pythagoras question. So again this is the radius of the earth and

  • you are trying to find the approximate distance between you and the horizon. So if we call

  • this x (that's the distance here). So then if we redraw the triangle, we have x here,

  • 6400km here and, in total, 6411.6 here and so by Pythagoras which in full of course is

  • this and by rearranging this to get x; as the result, you find the x, the approximate

  • distance between you and the horizon of the earth is roughly 386km.

  • The second question which is I'm going to go through goes as follows. A rocket of mass

  • m is to be launched from the surface of a rogue planet with mass M and radius R and

  • no atmosphere. By making reasonable assumptions about the distance between the planet and

  • any nearby galaxies, find the escape velocity required for the rocket to overcome the gravitational

  • field of the planet.

  • You might be wondering what the reasonable assumptions mentioned in the questions might

  • mean. And you just really need to think about what the effect of other planets close by

  • to this planet might be. So if there are planets close to the rogue planet, it's likely that

  • their gravitational field that have an effect on the motion of the rocket. Therefore, the

  • assumption that you need to make is the distance between this planet and any nearby planets

  • is very, very large and, therefore, only the gravitational field of the rogue planet is

  • important in this question. So for this question, I'll go straight into drawing a diagram

  • as it might make it clearer as to what you need to do to solve this problem. Say this

  • is the planet and we can mark on here that this is the radius big R. Now if we draw the

  • rocket to be here at any moment in time, we can label the distance from the rocket to

  • the center of the earth as little r. So this is just something that we can define. Say

  • in another given time, the rocket has now moved. So it's got a little further and

  • we are going to say that the distance between this instance and this instance is delta r

  • (just to symbolize a little distance). So we know that as the rocket is moving, there

  • must be a force due to the gravitational field of this planet acting on the rocket and this

  • force is going to be in this direction which we can call big F and we know in this instance

  • it will also be acting obviously with a different value which is given by the formula F equals

  • big G and then the mass of the planet which is capital M, the mass of the body upon which

  • the force is acting which is the little m over the distance between the two bodies which

  • we have to find as r2. Now with kinetic energy questions, you often immediately think of

  • energy balancing equations. So this might help in this problem. One energy balance equation

  • that we know is that the work done is equal to force times distance. Although we don't

  • quite know how we are going to get to kinetic energy through this, it might be worth a try.

  • We know that the force on the rocket is going to be given by the equation that we just wrote

  • down and if you don't remember this equation in the interview or you haven't seen it

  • before just as an example in an interview if you can't think of the equation or you

  • really don't know it; if you just state it, say “I'm really sorry I don't think

  • I can't quite really remember the formula of the equationThey will usually give

  • it to you as it will help you solve the question and they just don't want you to stop in

  • your tracks so they will help you if you forget things that might be useful. So yes force

  • times this force times the little distance. So we are working out the work that's done

  • for the rocket moving from here to here. So we will do times delta r. Now this here is

  • just an equation for the little amount of work done moving the rocket from this position

  • to this position which is just an arbitrary small distance. So to get the total amount

  • of work that will be needed to get the rocket from the surface of the earth as specified

  • in the question all the way to outside the gravitational field of the planet we will

  • need to sum all these little works done from bigger to infinity which is where the gravitational

  • field of the planet will end. Now if this isn't an intuitive step and you don't

  • get it in the interview, they may again the interviewers may again help you so that you

  • might be able to proceed further with the question. So don't panic.

  • Therefore the total work done which I'm going to write as w will be equal to the integral

  • between big R (so the radius of the planet) and infinity of this. And now you can see

  • it's just an integral but we need to calculate to get the work done. So to do the integral,

  • you can rewrite the over r2 as r to the power of -2 which makes it easier and then you can

  • see that by adding 1, dividing by the new power you get minus … r to -1 which you

  • can put on the bottom again between r to infinity. Now this when you put the limits in, the first

  • limit you put in is infinity obviously dividing by infinity is going to give you zero and

  • then the next step is you are doing is minus and then inserting large R; so you end up

  • with a minus minus big G big M little m over big R. Now this is just the total work done.

  • So I've just moved the result of this integral up here to save space for the next bit of

  • the question. As I have said in the beginning, when you think of kinetic energy questions

  • you may think of work done and energy balance equations. So now we have the total work needed

  • to get the rocket from here to outside the gravitational field. Through energy balance,

  • you know that the work done that is needed to do this must be equal to the initial kinetic

  • energy that the rocket has when it's at the surface of the planet. Therefore, we can

  • write that the result of our integral must be equal to half mv squared. From now on,

  • it's just rearranging to find the v which is the escape velocity, as specified in the

  • question. So mv2 is 2GFm over big R; therefore, in the end you get v as equal to 2GbigM/R

  • as the two ms cancel and the whole thing square rooted. And this is the formula for the escape

  • velocity. So these were the two interview questions. I hope you found them useful. If

  • you want to see anymore, go to the website that I mentioned earlier, I want to study

  • Engineering.org. But if I were to give any tips for the interview, I would say try not

  • to panic I know it's really hard and obviously you are going to feel stressed. But if you

  • forget anything in a spark of moment, if you misremember an equation or if you literally

  • can't see where this question is going, don't be afraid to admit that. The interviewers

  • are there to help and I'm sure teacher or whoever might have been telling you that already.

  • You may not believe but it is true they will try and help you through a question they won't

  • just leave you in a alert they just want to test you with things that you haven't seen

  • before so maybe using equations that you might have seen in Math and Physics for example

  • the gravitational force equation and then use it in a way that you might not be familiar

  • with. So they just want to see how well you pick up new concepts or at least that's

  • the idea that I got from my interview and speaking to my interviewers who are now also

  • my supervisors. That is generally the thing that they are trying to do or, at least in

  • my college, that's what they are trying to do. So try and not to panic and don't

  • be afraid to admit if you don't know something. I quoted FM = ma in my interview and they

  • still let me in. So don't worry if you slip up. Try and enjoy it these are some of the

  • most renowned academics in the engineering field who will be interviewing you probably.

  • They really are there to try and test you obviously but they will also help you through

  • it. So they are not the enemy. So hopefully that was useful and I wish you all good luck.

Hi, my name is Madeleine and I've just finished my second year of Engineering at Jesus College,

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