Subtitles section Play video Print subtitles - [Instructor] So it turns out solving electric field problems gets significantly harder when there's multiple charges. I mean, theoretically it shouldn't, but people have a lot more problems when there's multiple charges involved. So say the question is this; let's say we wanted to know what's the magnitude and direction of the net electric field, i.e. the total electric field, created halfway between these two charges down here. So you've got a positive eight nanocoulomb charge and a negative eight nanocoulomb charge, and they're separated by six meters from the center to center distance. But what we want to know is what's the total electric field that they both create right there? So each charge is going to create an electric field at this point, and if you add up like vectors, those electric fields, what total electric field would you get? Now at first you might think, well you should just get zero, right? It's very tempting to say that the electric field is just gonna be zero there because you've got a positive eight nanocoulomb charge and a negative eight nanocoulomb charge and those should just cancel, right? But you have to be really careful, turns out that's not true here, this is not gonna be true. And to see why, first you should just draw what is the direction of each field at that point? So this positive eight nanocoulomb charge is gonna create a field at this point that goes radially away from the positive charge, and so it's gonna go to the right. And I'm not even looking, so when I'm trying to find the electric field from this positive charge over here, I'm not even paying attention to this negative charge, I pretend like this negative charge doesn't even exist. Then I just ask what field would this positive charge create? It's still gonna create that field whether this negative charge is over here or not. And now I can do the same thing, I can ask what field would this negative charge create? And I'm gonna pretend like this positive charge isn't even here. So negative charges create a field that go radially in. So over here radially in would point to the right. So these don't cancel. The negative charge created a field radially in, that was to the right, the positive charge created a field radially out of the positive charge, and that was to the right. So not only are these not gonna cancel, these are gonna add up to twice the fields cuz you're gonna add up these vectors, you just add them up if they're in the same direction, and you'll get two times the contribution from one of them. So it's not always the case, in other words it's not always the case that a negative charge and a positive charge have to cancel their electric fields. Those electric fields might point the same direction, so you gotta be careful. So how do we find this net electric field then, what do we do? Well we're gonna say that, all right, this electric field, the first thing I can say is this net electric field is just gonna point in the x direction. So this is just really in the x direction, all I really care about is the electric field in this horizontal direction, and it's gonna be equal to the sum of the electric fields each charge creates there. So we'll do the blue charge first, that's gonna be k times the blue charge divided by r squared. Then we'll do the yellow charge, it's gonna be plus k, the charge of that yellow charge, divided by r squared. So we'll plug in some values here, this k is always nine times 10 to the ninth, and the q of this blue charge was positive eight nanocoulombs, nano is 10 to the negative ninth, I like using nano because then that negative nine cancels with that positive nine. And what distance do I put in here? A lot of people wanna put in six, but that's not what I want. Think about it, I want the net electric field halfway between the two charges, so the r that I care about in this electric field formula is the distance from the charge to the point where I want to determine the electric field, and in that case this is three meters. So for this case, from the charge to the point I'm concerned about finding the field is three meters, not six meters. If we were finding the force these charges exert on each other, then I'd have to use six meters, but that's not what I'm finding, I'm finding the field each charge creates at this halfway point. So I'm gonna plug in three meters down here, and I can't forget to square it. And now I have to be careful, just cuz my charge is positive doesn't necessarily mean that the contribution to the electric field is positive. You have to check, you can't rely on the sign of this charge to tell you whether the contribution's positive or negative. I've gotta look at what direction it points, the direction this positive charge creates a field is to the right. Since that's typically the direction we call positive, then I'm okay with calling this entire term here positive. Then we're gonna have another term. I'm gonna leave off the plus or minus cuz, I mean, it might be plus, it might be minus, we'll leave that off for a second, we'll have to decide when we know what direction it goes. So we do nine times 10 to the ninth, and then the charge is negative eight nanocoulombs, but I am not gonna plug in the negative sign. Oops, and I left off coulomb on the other one here, sorry. And then again, the distance I want is from the charge to the point where we want to find the field, and that again is three meters, and we can't forget to square it. So should this contribution be positive or negative? I can't rely on the negative sign to tell me that, I've gotta look at what direction it goes. Since it goes to the right, that's the positive direction, so this is gonna be plus, these add up, these both go the same direction, the positive direction, so the total net electric field is just gonna be both of these added up. So if I do this, if I square this three I'm getting nine, and nine divided by nine is just one, so I get eight newtons per coulomb, and then this term is really the same thing, nine is divided by nine so that goes away, 10 to the ninth cancels with 10 to the negative ninth and all I'm left with is this eight, so it'd be plus eight newtons per coulomb. So each charge is contributing eight newtons per coulomb of electric field at this point which means that the total net electric field would just be 16 newtons per coulomb at that point. That is the net electric field, that's the magnitude of the net electric field at that point between them. And which way does it go, what's the direction? It goes to the right cuz both of these vectors pointed to the right so the total is gonna be twice as big as one of them and also to the right. Now if you have a case like this and both terms, you know both terms are gonna be equal, you can just write one of them down and multiply by two, you don't have to just add them both up, but I wanted to show you this way so you could see how everything works out. And in the end we get 16 newtons per coulomb for the total field which points to the right. Now what if we changed this, what if we made this instead of a negative eight nanocoulomb charge we made this a positive eight nanocoulomb charge? Well it would no longer create an electric field that points to the right. Positive charges create fields that point radially away from them, so it would create its electric field to the left, which means down here when we find