In the diagram above, O is the center of the circle, |SQ| = |QR| and ∠PQR = 68°. Calculate ∠PRS
- A.
34^{o} - B.
45^{o} - C.
56^{o} - D.
62^{o} - E.
68^{o}
Correct Answer: Option A
Explanation
From the figure, < PQR = 68°
(therefore) < QRS = < QSR = (frac{180 – 68}{2}) (base angles of an isos. triangle)
= 56°
(therefore) < PRS = 90° – 56° = 34° (angles in a semi-circle)