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  • He's known as one of the mathematicians with perhaps the most natural talent for maths

  • It's a man called Ramanujan. He was an Indian mathematician. He started with no formal training

  • in mathematics. But just by working alone, isolated, he was able to come up with all these mathematical facts,

  • these theorems, all by himself. Some were rediscoveries of things that were already known

  • Some were new! And he sent these to Cambridge mathematicians and they recognized his talent

  • And he was invited to come to Cambridge and show off what he could do

  • When we're filming this - a film has just come out all about Ramanujan

  • this film just concentrated on one achievement. And it was something to do with partitions.

  • So partitions is about the number of ways that we can break down a number.

  • We take a number, an integer, and how many ways can we break it down into positive parts?

  • And to prove that I'm a serious mathematician, I'm going to illustrate this by using a DUPLO here.

  • Let's say we take the number four, and I've got four units of DUPLO there,

  • how many ways can I break this down into positive parts? So I could start with this. It's a tower of four.

  • Or, I could break it down, right? I could have a three and a one. Right? Or, I could have a two, a one, and a one.

  • Or I could break it down again, I could have one, one, one, one, and there is one I've missed there if you noticed

  • I have missed out breaking it down into two and two. So in fact, there are five ways to break this down.

  • So we draw this out. We could either draw it like this: one, two, three, four. We can do a three and a one.

  • Like that. Two, two. We could have two, one, one. One, one, one, one, like that.

  • So this is what mathematicians actually do, they do it this this way because by seeing it as a picture,

  • you can actually make conclusions about partitions which are easier to see.

  • The French do this slightly differently. The French draw them like this: you can have a row of four like that.

  • And you can have a row of three with a row of one like that, so it's the other way around.

  • Or you could it like this, above. And then the last one here: one, one, one, one. So it's a slightly different way of doing it.

  • My favorite foot note from a textbook - do you have a favorite footnote from a textbook? - oh, I know I do.

  • Favorite footnote from a textbook was by Ian MacDonald who said

  • "if you want to do the French notation, you should read this textbook while looking upside down and in a mirror"

  • So I get to say this for myself for the first time!

  • If you want to use the French notation, watch this video upside down and in a mirror.

  • So let's look at the sequence of partitions. So the sequence is this:

  • one, two, three, five, seven, eleven, fifteen, twenty-two, thirty, forty-two, and so on like this.

  • Ok, so when we were looking at partitions before, that's this one here, there were five partitions of four.

  • So if that's breaking down the number four, there are five ways of doing it.

  • If you wanted to break down the number five, there'd be seven ways of doing it, and so on.

  • So, these numbers get larger and by the time we get to something like one hundred,

  • how many ways can we break down the number one hundred. If we did that, it's going to be a large number.

  • It's going to be one hundred and ninety million, five hundred and sixty-nine thousand, two hundred and ninty two.

  • So these get really large. Now, it becomes very difficult to calculate these partitions by hand.

  • Wouldn't it be nice to have a formula that helps us work out these partitions?

  • So, then if I have a formula, you can give me a number, and I can tell you how many ways to break that down.

  • Oh, fantastic! And this is the problem that Ramanujan decided to tackle.

  • So there were some formulas before Ramanujan, which go back to Euler. Not particularly pretty formulas,

  • but I can show you what they look like. Should I do that?

  • Ok, so, I'm gonna draw out a polynomial using partitions as coefficients.

  • It means it's gonna look like this: one plus, I'm gong to have, plus x plus,

  • now I'm going to have x squared next and I'm going to use how many ways to break down two.

  • There, which is two ways of doing that. So, if I have x cubed next,

  • I want how many way to break down three and there are three ways of doing that.

  • And I would keep going like this. If I had x four, we know how many ways to break that down, right?

  • There are five ways of doing it. And then it's seven for x five and so on and so on.

  • So this is a very mathsy looking thing. In other words, if you like this notation, it means "sum".

  • If I want to sum - these are called partitions of n and then it's times x to the power of n. And you do that all the way up to infinity.

  • Now, what Euler saw was this was equal to, this is equal to - I'm going to use another symbol here: this symbol,

  • which is a capital pi, it means product, it means you are multiplying these things together.

  • (In background) Not three point one four

  • It's not three point one four, yeah, we're limited in how many letters we've got to use so we're using pi here for product.

  • The product of one over one minus x to the k. Yeah, we've got this. It's from k equals 1 to infinity.

  • So we've got something that we're multiplying together is equal to this polynomial. This is a way of working out partitions.

  • And it's what you used to do classically. And so if you want to work out the partitions of one hundred,

  • you could use a formula like this and actually do the calculation. But it's not particularly easy.

  • But that is what they used to do if they had to do it by hand,

  • and it's what your computer would do if it wants to work out partitions, it would use a formula like that

  • Ramanujan had an amazing intuition for numbers.

  • Another Cambridge mathematician called John Littlewood said that all the positive integers were Ramanujan's personal friends.

  • Which sounds like an utter nightmare to me, having infinitely many personal friends,

  • imagine the Christmas card list, sounds terrible. So let's look at some of the things he noticed about partitions.

  • I guess this is something that attracted him to the subject. Looking at partitions of, let's say,

  • a number that looks like this: five k plus four. Okay, so if you have a number like that, it ends with a four or a nine.

  • Four, nine, fourteen, nineteen, so these numbers. So you have a number like that, you notice something.

  • You notice that the number of ways of breaking it down is divisible by five. So there's a fact that he noticed.

  • The first example: if we took k equals zero, we're looking at - if it's zero - looking at partitions of four.

  • Ok, we did that, alright, how many ways were there to do it? There were five ways of doing it.

  • It's divisible by five. Great! What about partitians of nine? So if you have k equals one,

  • this would be partitions of nine, that's the next step up. How many ways of doing that? And if you work it out,

  • I can tell you that there are thirty ways of doing that and, hey, again it works, it's divisible by five.

  • It always appears to be the case. Ramanujan was able to show this,

  • and he was able to show a couple of things that were similar to this as well.

  • Like if you had partitions of a number that looked like this: seven k plus five, then that is divisible by seven.

  • Or if you had partitions that look like this: eleven k plus six, then this is divisible by eleven.

  • So he had these little facts. And if you see that pattern, it does seem to appear like the next one should be something like this

  • partitions of thirteen k plus seven is divisible by thirteen. And that is not right. That is incorrect.

  • The pattern doesn't hold. Ramanujan found these three and he found no other formula like this, and he thought

  • "well that's it, those are the only formula's we've got. The next one doesn't hold,

  • the others don't appear to hold." Eventually fifty years later, they did solve this. There is one that looks like this,

  • it's not as simple as what they thought. Seventeen thousand, three-hundred and three k plus two three seven is divisible by thirteen.

  • Which is nothing like what Ramanujan found before. And it seems crazy but now we know that we have a formula like this for every prime.

  • But they're just not as nice as the first three that was found by Ramanujan.

  • But it's still not the big formula they wanted to find. Let's have a look at the big formula, the main punchline.

  • Ok. Number of partitions is one over four n square root of three multiplied by the exponential of pi.

  • That's a traditional pi. That's three point one four. Times the square root of two n over three.

  • So that's a nice, closed formula for how many partitions there are. That twiddle sign, if you notice,

  • means it's not equals. It means it's an approximation, but it's an approximation that gets better with larger values.

  • So this is actually getting better and better as you go along the sequence. So if we did this with an example

  • Let's do one hundred, right? We know what the one hundred value was, and if we did this with one hundred, put one hundred in here, we would get

  • one hundered and ninety-nine million, two hundred and eighty thousand, eight hundred and ninety-three

  • Now this is in this right area for the true value. But it's about four point six percent off. Maybe it's not the best,

  • but again this formula is getting better with larger values.

  • But I can do better than that because this formula I gave you here is actually just the first term in a series.

  • So this can actually become more accurate, in fact it becomes equals.

  • So what Ramanjun was able to do was use his full formula

  • and you just needed the first five terms to work out the value for partitions of two hundred to the nearest integer.

  • And you can actually do that using his own formula. So these are not particularly easy to calculate,

  • but the largest value we've calculated so far is something around one hundred million million million,

  • so it's twenty zeros, a massive number. And the number of partitions,

  • so the number of ways of breaking that down is something that has eleven billion digits.

  • So there are a huge number of ways of doing it. And the reason partitions are important: partitions are used in the mathematics of shuffling.

  • Like shuffling a pack of cards! Alright, so think of a shuffle like that. But,

  • there are lots of things in maths that are actually a shuffle. You can think of -

  • and even in Physics like shuffling energy. So you know energy isn't created or destroyed it just gets moved around, right?

  • It just gets shuffled; it gets conserved. And underneath that, the maths is the same:

  • it's the maths of shuffling and it's the maths of partitions.

He's known as one of the mathematicians with perhaps the most natural talent for maths

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