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  • - [Instructor] What we're going to do in this video

  • is introduce ourselves

  • to the quotient rule.

  • And we're not going to prove it in this video.

  • In a future video we can prove it using the product rule

  • and we'll see it has some similarities to the product rule.

  • But here, we'll learn about what it is

  • and how and where to actually apply it.

  • So for example

  • if I have some function F of X

  • and it can be expressed as the quotient

  • of two expressions.

  • So let's say

  • U of X

  • over V of X.

  • Then the quotient rule tells us

  • that F prime of X

  • is going to be equal to

  • and this is going to look a little bit complicated

  • but once we apply it, you'll hopefully

  • get a little bit more comfortable with it.

  • Its going to be equal to the derivative

  • of the numerator function.

  • U prime of X.

  • Times the denominator function.

  • V of X.

  • Minus

  • the numerator function.

  • U of X.

  • Do that in that blue color.

  • U of X.

  • Times the derivative of the denominator function

  • times V prime of X.

  • And this already looks very similar to the product rule.

  • If this was U of X times V of X

  • then this is what we would get if we took the derivative

  • this was a plus sign.

  • But this is here, a minus sign.

  • But were not done yet.

  • We would then divide by

  • the denominator function squared.

  • V of X

  • squared.

  • So let's actually apply this idea.

  • So let's say that we have F of X

  • is equal to

  • X squared

  • over cosine of X.

  • Well what could be our U of X

  • and what could be our V of X?

  • Well, our U of X

  • could be our X squared.

  • So that is U of X

  • and U prime of X would be equal to two X.

  • And then this could be our V of X.

  • So this is V of X.

  • And V prime of X.

  • The derivative of cosine of X with respect to X

  • is equal to negative sine of X.

  • And then we just apply this.

  • So based on that

  • F prime of X

  • is going to be equal to

  • the derivative of the numerator function

  • that's two X, right over here, that's that there.

  • So it's gonna be two X

  • times the denominator function.

  • V of X is just cosine of X

  • times cosine of X.

  • Minus

  • the numerator function

  • which is just X squared.

  • X squared.

  • Times the derivative of the denominator function.

  • The derivative of cosine of X

  • is negative sine X.

  • So, negative

  • sine of X.

  • All of that over

  • all of that over

  • the denominator function squared.

  • So that's cosine of X

  • and I'm going to square it.

  • I could write it, of course, like this.

  • Actually, let me write it like that

  • just to make it a little bit clearer.

  • And at this point, we just have to simplify.

  • This is going to be equal to

  • let's see, we're gonna get

  • two X times cosine of X.

  • Two X

  • cosine of X.

  • Negative times a negative is a positive.

  • Plus, X squared

  • X squared

  • times sine of X.

  • Sine

  • of X.

  • All of that over

  • cosine of X squared.

  • Which I could write like this, as well.

  • And we're done.

  • You could try to simplify it, in fact,

  • there's not an obvious way to simplify this any further.

  • Now what you'll see in the future

  • you might already know something called

  • the chain rule, or you might learn it in the future.

  • But you could also do the quotient rule

  • using the product and the chain rule

  • that you might learn in the future.

  • But if you don't know the chain rule yet,

  • this is fairly useful.

- [Instructor] What we're going to do in this video

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